There is a little nice
theorem which allows us to find how many
divisors
a
number has, if we know its
Prime Factorization.
Consider an
integer number,
n.
Suppose
n = (p1)a1
* (p2)a2 * ... * (pk)ak
,where
p1...
pk are
prime numbers,
and
a1...
ak are the corresponding
exponents.
Then, you can easily find out how many divisors n has (say S), with the following
simple
formula:
S = (
a1+1)*(
a2+1)*...*(
ak+1)
Proof
Suppose as above n = (p1)a1
* (p2)a2 * ... * (pk)ak
The divisors of the number n then are those with prime factorizations with the same primes as n but with powers no bigger than the powers ai. Each power can be chosen independently, so there are (a1+1)(a2+1)...(ak+1) such divisors.
Let's see that through an
example. Consider 24.
24 = 2
3 * 3
1
So, with the above formula we take (3+1)*(1+1) = 8 divisors
Let's check this.
Divisors of 24: 1, 2, 3, 4, 6, 8, 12, 24
OK, they are 8.
Source: The Papyrous, Larousse, Britannica Encyclopedia