The number of possible states of the universe (idea)

There are about 10⁷⁹ atoms in the universe.

The visible universe is about 10²⁶ metres across, or around 10³⁶ angstroms across. This gives a volume of the visible universe of around about a googolplex (10¹⁰⁰) angstrom cubed.

Let us assume that all atoms are non-identical, are stationary, and exist in well defined areas, and can co-locate.

With some simple mathematics, it can be seen that the number of possible positions for n atoms in this model is 10¹⁰⁰ⁿ. In other words, the power of the number will gain an additional two zeros for each additional atom. So for a four atom universe at the current size, it will be 10^100,000,000, or a 1 followed by one hundred million zeros. As it is, the answer comes to:

10^{100,000,000,000,000,000,000,000,000}. This is a large number, to say the least. (a 1 followed by one hundred thousand quadrillion noughts, or a 1 followed by a septillion noughts. If you can visualise a septillion, /msg me...)