One of the most common
classes of
vector space encountered in
mathematics, especially
functional analysis.
Definition: A Banach space is a normed vector space which is complete in the metric induced by its norm.
That is, start with a vector space E over the real numbers R or complex numbers C (or you could use another complete normed field such as the p-adic numbers, but that's a whole 'nother can of worms). Call your field of choice k. Define a norm || || on E, which is a notion of absolute value or distance from zero that is compatible with the vector space structure on E:
If you think of ||x|| as the
distance of x from
zero, then || || defines a
metric d on E, by setting d(x, y) = ||x - y||. This turns E into a
metric space. If E is
complete under this
metric, then we call E a
Banach space.
Every finite-dimensional vector space over the real or complex numbers is a Banach space, using the conventional Euclidean norm
||(x1, ..., xn)|| = (|x1|2 + ... + |xn|2)1/2.
(A perverse way to describe this norm on Rn would be to call it L2R{1, ..., n}. See below.) In fact, it is not hard to prove that every finite-dimensional Banach space is isomorphic to one of these. The interest of Banach spaces lies in the many nontrivial infinite-dimensional examples. These include:
- CR(X) or CC(X), the real- or complex-valued continuous functions on a compact metric space X, using the "uniform norm"
||f||∞ = sup {|f(x)|: x ∈ X}.
(Why the ∞ subscript? Because this is the same norm used for L∞, in the next item.)
- Lp(μ), the Lebesgue space of functions on a measure space (X, μ) whose pth powers are integrable; when 1 ≤ p < ∞, the Lp norm of a function f is the pth root of the integral of |f|p over X:
||f||p = (∫X |f|p dμ)1/p.
For p = ∞, the corresponding space L∞(μ) is the space of measurable functions f on X which are essentially bounded, that is there exists some bound N such that {x ∈ X : |f(x)| > N} has μ-measure zero. The infimum of all such N is called the essential supremum of |f| on X, and we put
||f||∞ = ess supx∈X |f(x)|.
(Why is this the same norm as above? Because a continuous function, which is essentially bounded, is bounded.) When the total measure μ(X) is finite, L∞ is actually the intersection of Lp for all 1 ≤ p < ∞; but this is no longer true when X has infinite total measure.
Because Lebesgue integration ignores sets of measure zero, the elements of Lp are actually not functions, but equivalence classes of functions which are equal almost everywhere. The fundamental fact of Fourier analysis is an isometric isomorphism between L2(T) and L2(Z), where Z is the integers and T is the unit circle. (The latter space is frequently written l2, but with a script lowercase 'ell'.) Elements of these two spaces are periodic functions and Fourier series respectively.
- Ck(X), the space of k times differentiable functions on a compact smooth manifold X. Although, as sets of functions, Ck(X) is a subset of C(X), it is not a closed subspace of the Banach space C(X), because a uniformly convergent sequence of differentiable functions need only be continuous, not differentiable. To make Ck(X) into a Banach space we therefore need to restrict the notion of convergence by changing the norm. Roughly speaking, the Ck norm of a Ck function f on X is the sum of the uniform norms of f and its first k derivatives; there are some technical details involved in computing the norms of the derivatives, since they are not numbers or matrices but symmetric tensor fields on X. Unfortunately C∞(X), the space of infinitely differentiable functions on X, is not a Banach space, but only a Fréchet space. Also, if X is not compact (as is the case for open subsets of Rn, for instance) these spaces are more complicated, which accounts for some of the technical difficulties in distribution theory.
- Many more technical examples, including the Sobolev spaces near and dear to my heart.